1.  The age of the Earth is approximately how many years old?  a) 5 hundred,
b) 5 thousand, c) 5 million, d) 5 billion, e) 5 trillion

2.  The human population of the Earth is approximately how many individuals?
a) 50 million, b) 500 million, c) 5 billion, d) 50 billion, e) 500 billion.

3.  What is the approximate maximum travel distance apart two places on Earth
can be?  a) 2 thousand miles, b) 5 thousand miles, c) 10 thousand,
d) 20 thousand miles, e) 50 thousand miles.

4.  How far, approximately, in miles, is the distance to the nearest star
(Sol, our sun) from here, in miles?  a) 1 million, b) 100 million,
c) 10 billion, d) 1 trillion, e) 100 trillion.

5.  How far, approximately, in miles, is the distance to the second nearest
star (Alpha Centauri) from here?  a) 30 million, b) 30 billion, c) 30 trillion,
d) 30 quadrillion, e) 30 quintillion.

6.  What is the approximate number of atoms in your body?  (Avagadro's number =
6x10^23 [10^23 means 100000000000000000000000]) a) 10 quadrillion,
b) 10 sextillion, c) 10 octillion, d) 10 decillion, e) 10 gadzillion.

7.  In what language are the above numbers given?  a) English, b) American,
c) both of the foregoing, d) neither of the foregoing, e) all of the foregoing.

8. The Roman numeral MCMXCIV multiplied by itself equals approximately
                                    _______     _________
a) MMCCMMXXCCIIVV, b) MMMMCXXVI, c) MCMXCIV, d) MMMCMLXXVMXXXVI,  e) ZMCMLXXXVI

9. What is the number 1994 multiplied by itself?  Exactly.  a) 3976036,
b) 3940, c) 57976451, d) 8760004, e) 8760005

10. What is 1.994x10^3 squared? [remember, 10^n means 1 followed by n zeros,
10^3 means 1000] Three significant figures.
a) 8.76x10^6, b) 5.80x10^7, c) 3.98x10^3, d) 3.98x10^6, e) 3.98x10^9

11. In 1625, Peter Minuit purchased Manhattans' Island for $24. If Chief Heap
Plenty Wampum had invested his $24 at 10% compound interest, approximately
what would be the value of the investment today? a) $50 thousand,
b) $50 million, c) $50 billion, d) $50 trillion, e) $50 quadrillion.

12. As of 29 July 87, there were 6067 cases of AIDS reported in Europe, with
a doubling time of 9 months. If this rate of spread were to continue for
another twelve years, how many cases of AIDS would be expected by the turn of
the century? a) 58 thousand, b) 580 thousand, c) 5.8 million, d) 58 million,
e) 580 million.

13.The doubling time of AIDS cases in the United States was about 14.5 months
and the number of diagnoses was approximately 47,000 as of 1 Dec 87.  At this
rate, what is the expected number of AIDS diagnoses in the US in 8 years (the
average incubation time)?  a) 0.5 million, b) 1 million, c) 5 million, d) 10
million e) 50 million.